find the distance between the points (-3, 4) and (6, -2)
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S O L U T I O N :
Let, R(-3 , 4) & S(6 , -2)
Here,
- x1 = -3
- y1 = 4
- x2 = 6
- y2 = -2
Applying distance formula,
XY = √(x2 - x1)² + (y2 - y1)²
[ Put the values ]
⟹ RS = √(6 - (-3)² + (-2 - 4)²
⟹ RS = √(6 + 3)² + (-6)²
⟹ RS = √(9)² + (-6)²
⟹ RS = √81 + 36
⟹ RS = √117
Therefore,
The distance between the points (-3, 4) and (6, -2) is √117.
For information :
Section formula,
⟹ x = (mx2 + nx1 / m + n) OR. y = (my2 + ny1 / m + n)
Midpoint formula,
⟹ x = x1 + x2 / 2 OR y = y1 + y2 / 2
Centroid formula,
⟹ x = x1 + x2 + x3 / 2 OR y = y1 + y2 + y3 / 2
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