Question

. Find the distance between the points ( 5 sin60,0) and (0,5sin30).

Answer 1

using distant formula the distance b/w these points is

$\sqrt{(5 \sin(60) - 0)^{2} + (5 \sin(30) - 0)^{2} }$
$\sqrt{25 { \sin(60) }^{2} + 25 { \sin(30) }^{2} }$
$\sqrt{25( { \sin(60) }^{2} + { \cos(60) }^{2} ) }$
$\sqrt{25}$
$5$

Answer 2

Answer:

5 units *

Answer in the attachment

Step-by-step explanation:

I hope it will help you to proceed further....

@mandalsneha