Find the distance between the points ( -6, -1) and (- 6, 11).
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10
Solution:
Let the points are P (-6,-1) , Q(-6, 11)
Here , x1= -6 , y1= -1, x2= -6 , y2 = 11
Distance between two points,
PQ= √(x2-x1)² + ( y2 - y1)²
[By distance formula]
PQ= √ (-6-(-6))²+ (11-(-1)²
PQ= √ (-6+6)² + (11+1)²
PQ= √ 0² + 12²
PQ= √ 12² = √144 = √12×12 = 12
PQ= 12 units.
Hence, the Distance between two points = 12 units.
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Hope this will help you.....
Let the points are P (-6,-1) , Q(-6, 11)
Here , x1= -6 , y1= -1, x2= -6 , y2 = 11
Distance between two points,
PQ= √(x2-x1)² + ( y2 - y1)²
[By distance formula]
PQ= √ (-6-(-6))²+ (11-(-1)²
PQ= √ (-6+6)² + (11+1)²
PQ= √ 0² + 12²
PQ= √ 12² = √144 = √12×12 = 12
PQ= 12 units.
Hence, the Distance between two points = 12 units.
==================================================================================
Hope this will help you.....
Answered by
11
heya!
hope it helped uh.
hope it helped uh.
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