Question

Find the distance between the points (-6, -1) and (-6, 11).

Answer 1

step by step explanation

given points are, (-6,-1)

(-6,11).

distance = √(x2-x1)^+(y2-y1)^2

√(-6-(-6)^2+(11-(-1)^2

√(-6+6)^2+(11+1)^2

√(0)^2+(12)^2

√0+144

√144=12

the distance between the two points = 12

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Answer 2

$\underline{ \fcolorbox{red}{pink}{ \huge{Solution :}}}$

Let , the two points be A(-6,-1) and B(-6,11)

We know that , the distance between two points is given by

$\large \mathtt{ \fbox{D = \sqrt{ { (x_{2} - x_{1}) }^{2} + {( y_{2} - y_{1})}^{2} } \: \: }}$

Substitute the known values , we obtain

$\sf \mapsto D = \sqrt{ { (- 6 - ( - 6))}^{2} + {(11 - ( - 1))}^{2} } \\ \\ \sf \mapsto D = \sqrt{ {( 0)}^{2} + {(12)}^{2} } \\ \\ \sf \mapsto D = \sqrt{ {(12)}^{2} } \\ \\ \sf \mapsto D =12 \: \: units$

Hence , the distance between A(-6,-1) and B(-6,11) is 12 units

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