Question

find the distance between the points a(2,-3)and b (2,2)
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Answer 1

Answer:

Explanation:

Given :

• Points are a(2, -3) & b(2, 2).

To Find :

• Distance between them.

Formula to be used :

• Distance formula, ie,.. d = √(x2 - x1)² + (y2 - y1)²

Solution :

★Distance between them,

d = √(x2- x1)² + (y2 - y1)²

⇒ d = √(2 - 2)² + (-3 - 2)²

⇒ d = √(0)² + (-5)²

⇒ d = √(-5)²

⇒ d = √25

⇒ d = 5 units

Hence, Distance between them is 5 units.

Know to more:

• Section formula, ie,.. x = (mx2 + nx1/m + n) & y = (my2 + ny1/m + n).
• Midpoint formula, ie,.. x = x1 + x2/2 & y = y1 + y2/2.
• Centroid formula, ie,.. x = x1 + x2 + x3/3 & y = y1 + y2 + y3/3.
• Slope formula, ie,.. m = y2 - y1/x2 - x1.

Answer 2

$\Huge\tt{{\color{navy}{{\underline{AN}}}}{\color{blue}{{\underline{SW}}}}{\blue{{\underline{ER}}}}{\color{skyblue}{:}}}$

$\huge\color{navy}{\textbf{\textsf{GIVEN :-}}}$

• Points are a(2, -3) & b(2, 2)

$\huge\color{blue}{\textbf{\textsf{TO FIND :-}}}$

• Distance between them.

$\huge\color{blue}{\textbf{\textsf{FORMULA :-}}}$

• Distance Formula , i.e. d = √(x2 - x1)² + (y2 - y1)²

$\huge\color{skyblue}{\textbf{\textsf{SOLUTION :-}}}$

d = √(x2 - x1)² + (y2 - y1)²

→ d = √(2 - 2)² + (-3 - 2)²

→ d = √(0)² + (-5)²

→ d = √(-5)²

→ d = √25

→ d = 5 unit

Hence, distance between them is 5 unit.

Hope it Helps Buddy ♥️