Question

Find the distance between the points a (4,10) b(7,-6)

Answer 1

AnsWer :

16.49 units.

SolutioN :

Let's,

• Point be,
• A( 4 , 10 )
• B( 7 , - 6 )

Now, We know Distance Formula.

$\tt \dagger \: \: \: \: \: D_{istance} = \sqrt{ {(x_2-x_1)}^{2}+ {(y_2-y_1)}^{2} }$

Now, Let Find distance between point A and B.

We have,

• x1 = 4.
• x2 = 7.
• y1 = 10.
• y2 = - 6.

$\tt \dagger \: \: \: \: \: AB = \sqrt{{(7 - 4)}^{2} + {( - 6 - 10) }^{2} }$

$\tt \dagger \: \: \: \: \: AB = \sqrt{{(4)}^{2} + {( - 16 )}^{2} }$

$\tt \dagger \: \: \: \: \: AB = \sqrt{{16 } + {256}}$

$\tt \dagger \: \: \: \: \: AB = \sqrt{272}$

$\tt \dagger \: \: \: \: \: AB = 16.49 \: units.$

Therefore, the distance between point A and B is 16.49 Units.

MorE InformatioN :

Distance Formula :

$\tt \dagger \: \: \: \: \: D_{istance} = \sqrt{ {(x_2-x_1)}^{2}+ {(y_2-y_1)}^{2} }$

Mid-point Formula :

$\tt \dagger \: \: \: \: \: Mid-point =\Bigg[ \dfrac{x_1 + x_2}{2}, \dfrac{y_1 + y_2}{2} \Bigg]$