find the distance between the points a (7,3) and b(4,-1).
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It can be calculated by using the distance formulae.
The answer is 5 units.
Check the attachment for reference.
Hope it helps...
Regards,
Leukonov/Olegion.
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Let the two points be A ( 7,3) and B (4,-1)
A (7,3)
x1 = 7
y1 = 3
B(4,-1)
x2 = 4
y2 = -1
AB = √[(x2-x1)² + (y2 - y1)²]
AB = √[(4-7)² + (-1-3)²]
AB =√[(-3)² + (-4)²]
AB = √[9 + 16]
AB = √25
AB = 5
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