Question

find the distance between the points a(8,-3),(0,9) by using (4,-1) & (1,-3)
using the distance formula ​

Answer 1

Answer:

$\text{The distance between two points }(8,-3)\text{ and }(0,9)\text{ is}4\sqrt{13}$

$\text{The distance between the points (4,-1) and (1,-3) is }\sqrt{13}$

Step-by-step explanation:

$\text{The distance between two points }(x_1,y_1)\text{ and }(x_2,y_2)\text{ is}$

$\boxed{d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$

$\text{The distance between the points (8,-3) and (0,9) is }$

$d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$d= \sqrt{(8-0)^2+(-3-9)^2}$

$d= \sqrt{(8)^2+(-12)^2}$

$d= \sqrt{64+144}$

$d= \sqrt{208}$

$d= \sqrt{16\times\,13}$

$d= 4\sqrt{13}\:units$

$\text{The distance between the points (4,-1) and (1,-3) is }$

$d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$d= \sqrt{(4-1)^2+(-1+3)^2}$

$d= \sqrt{(3)^2+(2)^2}$

$d= \sqrt{9+4}$

$d=\sqrt{13}\:units$