Find the distance between the points a (sin theta, A cos theta) and (Cos theta, sin theta)?
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varun000:
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Answer:
The distance between the points is \sqrt2
Step-by-step explanation:
We have been given the points
(\cos\theta,\sin\theta),(\sin\theta,-\cos\theta)
We know the formula for distance between two points which is given by
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
d=\sqrt{(\sin\theta-\cos\theta)^2+(-\cos\theta-\sin\theta)^2}
d=\sqrt{\sin^2\theta+\cos^2\theta-2\sin\theta\cos\theta+\cos^2\theta+\sin^2\theta+2\sin\theta\cos\theta}
d=\sqrt{2(\sin^2\theta+\cos^2\theta)}\\\\d=\sqrt{2}
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