Question

Find the distance between the points (Cos theta,Sin theta)and(Sin theta,-Cos theta)

Answer 1

just a+b whole square formula

Answer 2

Answer:

The distance between the points is $\sqrt2$

Step-by-step explanation:

We have been given the points

$(\cos\theta,\sin\theta),(\sin\theta,-\cos\theta)$

We know the formula for distance between two points which is given by

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(\sin\theta-\cos\theta)^2+(-\cos\theta-\sin\theta)^2}$

$d=\sqrt{\sin^2\theta+\cos^2\theta-2\sin\theta\cos\theta+\cos^2\theta+\sin^2\theta+2\sin\theta\cos\theta}$

$d=\sqrt{2(\sin^2\theta+\cos^2\theta)}\\\\d=\sqrt{2}$