Find the distance between the points:
(i) (9,3) and B(15, 11)
(1) A(-6, -1) and B(9,-12)
(
(i
(v) P(a+b, a - b) and Q(a-b, a+b)
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Answer:
(I) 10 units
1) 18.6 units
v) √(4b^2+4a^2) units
Step-by-step explanation:
Use the distance formula :
d=√[(x2-x1)^2+(y2-y1)^2]
i) (9;3).........1 the first point in your graph
(15;11)......2 the second point
You then substitute them to your distance formula : d=√[(x2-x1)^2+(y2-y1)^2]
NB : Remember all this [(x2-x1)^2+(y2-y1)^2] is under a root( √ ).
x1= 9
y1= 3
( 9;3) from the first point
x2 = 15
y2= 11
(15;11) from the second point
You then substitute your points to the distance formula:
d=√[(x2-x1)^2+(y2-y1)^2]
=√[(15-9)^2 + (11-3)^2]
=√[(6)^2 + (8)^2]
=√(36 + 64)
=√100
= 10 units
And now that I have shown you a way to approach this problem, you can do the rest using the distance formula .
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