Question

Find the distance between the points P(2,-1) and Q(3,4)​

Answer 1

Answer:

$\huge\orange{5.1 \: units \: (approx)}$

Step-by-step explanation:

Given:

Co-ordinates of P = (2, -1)

Co-ordinates of Q = (3, 4)

According to the Q,

$> > PQ$

Using Distance Formula:

$> > \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} }$

$> > \sqrt{[3 - 2] {}^{2} + [4 - ( - 1)] {}^{2} }$

$> > \sqrt{(3 - 2) {}^{2} + (4 + 1) {}^{2} }$

$> > \sqrt{1 {}^{2} + 5 {}^{2} }$

$> > \sqrt{1 + 25}$

$> > \sqrt{26}$

$> > 5.099$

$\orange {> > 5.1 \: units \: (approx)}$

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Answer 2

Step-by-step explanation:

p(2, -1)=x1y1

Q(3, 4)=x2y2

distance between the two points =root(x2-x1)*2+(y2-y1)*2

=root (3-2)*2+(4+1)*2

=root (1)*2+(5)*2

root 1+25

root 26