Question

find the distance between the points p (2,3) and Q(4,1) using distance formula​

Answer 1

Answer:

2.828 units

Step-by-step explanation:

$pq = \sqrt{ {(4 - 2)}^{2} + {(1 - 3)}^{2} }$

$pq = \sqrt{ {(2)}^{2} + {( - 2)}^{2} }$

$pq = \sqrt{ 4+ 4 }$

$pq = \sqrt{8}$

And,

$\sqrt{8} = 2.828$

Answer 2

✪ Given :-

• Coordinates of P = ( 2 , 3 )
• Coordinates of Q = ( 4 , 1 )

✪ To Find :-

• Area of the triangle ABC

✪ Solution :-

$\red\bigstar\: \boxed{\bf \green{Distance = \sqrt{ {(x_2 - x_1)}^{2} + {(y_2}^{2} -y_1)} }}$

Here

• x₁ = 2
• x₂ = 4
• y₁ = 3
• y₂ = 1

Substitute values in formula

$\longmapsto \sf Distance = \sqrt{ {(4 - 2)}^{2} + {(1 - 3)}^{2} }$

$\longmapsto \sf Distance = \sqrt{ {(2)}^{2} + {( - 2)}^{2} }$

$\longmapsto \sf Distance = \sqrt{4 + 4 }$

$\longmapsto \sf Distance = \sqrt{8}$

$\longmapsto \sf Distance =2 \sqrt{2} \: unit$