find the distance between the points P(-2, 4,1) Q(1, 2,-5)
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Answered by
2
Answer:
We know, the distanve between two points (x
1
,y
1
,z
1
) and (x
2
,y
2
,z
2
)
Distance=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
+(z
2
−z
1
)
2
∴PQ=
(1−(−2))
2
+(2−4)
2
+(−5−1)
2
=
9+4+36
=
49
=7
Answered by
3
Hope this will help you.
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