Question

find the distance between the points P(-2, 4,1) Q(1, 2,-5)​

Answer 1

Answer:

We know, the distanve between two points (x

1

,y

1

,z

1

) and (x

2

,y

2

,z

2

)

Distance=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

+(z

2

−z

1

)

2

∴PQ=

(1−(−2))

2

+(2−4)

2

+(−5−1)

2

=

9+4+36

=

49

=7

Answer 2

Hope this will help you.