Question

Find the distance between the points p(3,2) and Q(-1,5)

Answer 1

Hey mate

Here is your answer

PQ=√(3+1)^2+(2-5)^2

PQ=√4^2+3^2=√16+9=√25

PQ= 5 units

Distance between P and Q is of 5 units

Answer 2

Answer:

$\large\bold\red{5\:Units}$

Step-by-step explanation:

Given,

Two points having Coordinate,

P (3, 2 ) and Q ( -1, 5 )

We have to find the distance between these two points.

Now,

we already know that,

if (a, b ) and (c, d) are two points , the the distance bwteen them is given by,

$\bold{\sqrt{ {(a - c) }^{2} + {( b - d)}^{2} } }$

Therefore,

according to this,

we get,

$= > PQ = \sqrt{ {(3 - ( - 1))}^{2} + {(2 - 5)}^{2} } \\ \\ = > PQ = \sqrt{ {(3 + 1)}^{2} + {( - 3)}^{2} } \\ \\ = > PQ = \sqrt{ {(4)}^{2} + {( - 3)}^{2} } \\ \\ = > PQ = \sqrt{16 + 9} \\ \\ = > PQ = \sqrt{25} \\ \\ = > PQ = 5$

Hence,

Distance between the points = 5 units