Question

find the distance between the points P(-6,7) and (-1,-5) ​

Answer 1

Step-by-step explanation:

(x1, y1) = (-6,7)

(x2, y2) = ( -1,-5)

pq=(x2−x1) 2 +(y2−y1) 2

pq= (−1−(−6)) 2 +(−5−7) 2

pq= (5) 2 +(−12) 2

pq= 25+144

pq= (x1, y1) = (-6,7)

(x2, y2) = ( -1,-5)

pq= (x2−x1) 2 +(y2−y1) 2

pq= (−1−(−6)) 2 +(−5−7) 2

pq= (5) 2 +(−12) 2

pq= 25+144

pq= 169

pq=13