Question

Find the distance between the points p(-6 7) and q(-1 -5)

Answer 1

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Answer 2

(x1, y1) = (-6,7)

(x2, y2) = ( -1,-5)

$pq = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} } \\ \\ pq = \sqrt{( - 1 - ( - 6)) {}^{2} + ( - 5 - 7) {}^{2} } \\ \\ pq = \sqrt{(5) {}^{2} + ( - 12) {}^{2} } \\ \\ pq = \sqrt{25 + 144} \\ \\ pq = \sqrt{169} \\ \\ pq = 13$

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