find the distance between the points P(-6,7) and Q(-1,-5)
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hi mate here is ur answer
the distance between two points can be determined by using the distance formulae
that is √(x1-x2)^2 + (y1-y2)^2
so here x1 = -6 ,x2 = -1
y1 = 7 ,y2 = -5
the distance between the two points p(-6,7) and q(-1,-5) is
√(-6-(-1))^2 + (7-(-5))^2
= √(-6+1)^2+(7+5)^2
= √(-5)^2 + (12)^2
= √25 + 144
= √169
= 13
therefore the distance between the two points is 13 units
hope it helps!!!
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