find the distance between the points p[a+b,a-b] and q[a-b,a+b]
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Answered by
35
let distance between joining of two points (x1,y1) and (x2, y2)
= √(x2-x1)²+(y2-y1)²
(x1,y1) = P(a+b ,a-b)
(x2, y2) = Q(a-b, a+b)
PQ =√[a-b -(a+b)]²+ [a+b-(a-b)]²
= √(a-b-a-b)²+ (a+b-a+b)²
=√(-2b)²+ (2b)²
=√4b²+4b²
=√8b²
=√(2*2)*2*b*b
=2b√2
= √(x2-x1)²+(y2-y1)²
(x1,y1) = P(a+b ,a-b)
(x2, y2) = Q(a-b, a+b)
PQ =√[a-b -(a+b)]²+ [a+b-(a-b)]²
= √(a-b-a-b)²+ (a+b-a+b)²
=√(-2b)²+ (2b)²
=√4b²+4b²
=√8b²
=√(2*2)*2*b*b
=2b√2
sandeepnegi9827:
thanku
Answered by
13
let distance between joining of two points (x1,y1) and (x2, y2)
= √(x2-x1)²+(y2-y1)²
(x1,y1) = P(a+b ,a-b)
(x2, y2) = Q(a-b, a+b)
PQ =√[a-b -(a+b)]²+ [a+b-(a-b)]²
= √(a-b-a-b)²+ (a+b-a+b)²
=√(-2b)²+ (2b)²
=√4b²+4b²
=√8b²
=√(2*2)*2*b*b
=2b√2
thanku
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