Question

find the distance between the points P( cos alpha -sin alpha) and q(- cos alpha , sin alpha)

Answer 1

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Answer 2

$\underline{\underline{\Huge\mathfrak{Solution ;}}}$

Given that ;-

$p = (cosx \: and - sina)$
$q = ( - cosx \: and \: sina)$

Now ,

$= > pq = ( \sqrt{(cosx - cosx^{2}) + sina - sina^{2} }$

$= > \sqrt{(2cosx^{2}) + (2sina^{2}) }$

$= > \sqrt{4cosx^{2} + 4sin^{2}a }$

$= > \sqrt{4(cos^{2}x + sin^{2} a) }$

$= > \sqrt{4}$

$= > pq = 2$

Therefore ,
Here, $<b>PQ = 2 Units.</b>$