Question

Find the distance between the points with coordinates (-3,4) and (5,-2)

Answer 1

Answer:

Input Data :

Point 1(xA,yA)(xA,yA) = (4, 3)

Point 2(xB,yB)(xB,yB) = (3, -2)

Objective :

Find the distance between two given points on a line?

Formula :

Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2

Solution :

Distance between two points = √(3−4)2+(−2−3)2(3-4)2+(-2-3)2

= √(−1)2+(−5)2(-1)2+(-5)2

= √1+251+25

= √2626 = 5.099

Distance between points (4, 3) and (3, -2) is 5.099

Answer 2

Step-by-step explanation:

Having the points A (-3,4) and B (5,-2) on the same plane.

We calculate the distance 'd' with the formula:

d = √(x2 - x1)² - (y2 - y1)²

= √(5 - (-3))² - (-2 - 4)²

= √(8)² - (-6)²

= √64 + 36

= √100

= 10

∴ The distance between the points with coordinates (-3,4) and (5,-2) is 10 units.