Find the distance between the two points (2.5) (7 6)
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Points P(7,5) and Q(2,5)
We know that the distance between two points
=(x2−x1)2+(y2−y1)2
Therefore,
PQ=(2−7)2+(5−5)2
PQ=(−5)2+(0)2
PQ=5 units
Hence, this is the answer.
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