find the distance between the two points (√3,-1) and (1,-√3)
Answers
Answered by
0
Given the points are (
3
+1,1) and (0,
3
).
Now the distance between the two points is,
(
3
+1−0)
2
+(1−
3
)
2
=
(
3
+1)
2
+(1−
3
)
2
=
2{(
3
)
2
+(1)
2
}
=
2⋅4
=
8
units
Answered by
1
since the ans is 0
therefore the distance of AB is 0
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