Question

find the distance between the two points P(-5,7) and Q(-1,3)​

Answer 1

Answer:

(PQ) ^2 = (x1 - x2)^2 + (y1 - y2) ^2

=( -5 - (-1)) ^2 + (7 - 3) ^2

=( - 5 +1)^2 + (4)^2

= (-4)^2 + (4)^2

= 16 + 16

= 32

PQ = root 32

=4 root 2

So, the distance is of 4 root 2

Answer 2

Using Distance Formula

$pq \: = \sqrt{ { (- 1 + 5)}^{2} + {(3 - 7)}^{2} } \\ \\ = > \sqrt{16 + 16} \\ \\ = > 4 \sqrt{2} \: units$

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