Question

find the distance between two
A(5, 4)and(5, -1)​

Answer 1

Answer:

the answer is 5units

Step-by-step explanation:

according to distance formula,

here x= 5,x2= 5 and y = 4,y2=(-1)

distance between A and B

=√(x2-x)²+(y2-y)²

=√(5-5)²+(-1-4)²

=√(0)²+(-5)²

=√0+25

=√25

=5 units

Answer 2

Given,

$\huge \tt A(5,4) \: \: \& \: \: \: B(5, - 1)$

To find : Measure of Distance between A & B

We know,

$\tt{}Distance \: \: Formula = \sqrt{ {(x_{\tiny{2}} - x_{ \tiny{1}} )}^{2} + {(y_{ \tiny{2}} - y_{ \tiny{ 1}} )}^{2} }$

Here,

$\small {\bf x_{\tiny{1}}= 5, \: y_{\tiny{1}}= 4, \:x_{\tiny{2}}= 5, \: y_{\tiny{2}}= -1 }$

Now,

$\small \text{Measure of AB} = \sqrt{ {(5 - 5)}^{2} + {( - 1 - 4)}^{2} } \\ \\ \rm \implies \sqrt{ {(0)}^{2} + {( - 5)}^{2} } \: \\ \rm \implies \sqrt{25} \: \: \: \: \: \sf= \red5 \: units$

Hence,

• Distance between A(5, 4) and B(5, -1) is 5 units.