Physics, asked by khanshazil584, 7 months ago

find the distance between two electrons when the repulsive force between them is equal to one electron weight​

Answers

Answered by Anonymous
1

Answer:

This is an interesting question because it is off the beaten path.

The answer below is highly hypothetical because it is based on the force being constant. The time lapse of one second, relatively speaking, is extremely “long” for the answer to be realistic. Nonetheless, here is one solution:

Use the Coulomb Force of repulsion to calculate the force: → F = 2.3 E - 24 N

Calculate the acceleration of each electron: → a = F / m = 2.53 E 6 m/s/s

In one second, each electron would travel: → 1.3 E 6 meters! Like I said, this is highly unrealistic. Chances are both electrons would have collided with other particles in the interim. Perhaps you may be interested in the solution for one microsecond instead of one second. Even then, the distance would be unrealistic. The next lower time frame would be a nanosecond. In that span of time, each electrons would have covered be 1.3 E - 3 meters (1.3 millimeters), a far more reasonable distance.

Two electrons are 1 m apart. How would you show that the force between them is 2.304×10^-5?

What is the repulsion force between 2 electrons that are 1m apart?

What distance would the repulsive force between two electrons have a magnitude of one Newton?

At what distance would the repulsive force between two electrons have a magnitude of 2.0 newtons?

How strong is the electron repulsive force?

According to Coulomb’s law , the magnitude of electrostatic force between any two stationary charged point particles is given directly given by the formula

F = K * [ ( q * Q ) / ( r * r ) ]

where K is a constant and has a magnitude of 9 * ( 10 raised to power 9 ) in SI units .

Q and q are the magnitude of charges on each of the point particles

And

r is the fixed distance between those two particles .

Answered by anujgodwe956
0

Answer:

q

1

=q

2

=q(say)

r=0.4nm=4×10

−10

m

F=51.84×10

−9

N

F=

4πϵ

o

r

2

q

1

q

2

⟹9×10

9

×

16×10

−20

q

2

=51.84×10

−9

⟹q

2

=16×5.76×10

−38

⟹q=4×2.4×10

−19

C

N=number of electrons

q=Ne⟹N=

e

q

N=

1.6×10

−19

4×2.4×10

−19

⟹N=6

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