Question

Find the distance between two parallel
lines 3x-4y-5=0 and 6x-8y+4=0.​

Answer 1

Answer:

Putting y=0 in 3x−4y+9=0, we get x=−3.

Thus, (−3,0) is a point on the line 3x−4y+9=0.

Length of the perpendicular from (−3,0) to 6x−8y−15=0 is given by

d=62+(−8)2∣−3×6−8×0−15∣=1033