Question

Find the distance between two parallel lines 5x+12y-7=0 and 5x+12y+32=0

Answer 1

Answer:

Distance between parallel lines is |C2-C1|

................

V(a^2 + b^2)

=(32+7)/v(25+144)=39/13=3

.

Answer 2

According to the information provided in the question.

It is stated in the preceding question that,

The presented information is 5x+12y-7=0 and 5x+12y+32=0

We need to find the distance between two parallel lines.

As a result, the simplify equation is,

$\mathrm{d}=\frac{|32-(-7)|}{\sqrt{5^{2}+(12)^{2}}}$

$=\frac{32+7}{\sqrt{25+144}}\\=\frac{39}{\sqrt{169}}\\=\frac{39}{13}\\=3$

Therefore the distance is 3.