Question

Find the distance between two points (-3by2,0) and (0,-2)
$( - 3$
​

Answer 1

Distance formula:

D=$\sqrt{ {( x_{2}-x_{1})}^{2} + {( y_{2}-y_{1})}^{2} }$

$x_{1} \: and \: x_{2} \: are \: x - coordinates \: of \: given \: points.$

$y_{1} \: and \: y_{2} \: are \: y-coordinates \: of \: given \: points.$

According to given points:

$x_{1} = \frac{ - 3}{2} \\ x_{2} =0 \: \: \: \: \\ y_{1} =0 \: \: \: \: \\ y_{2} = - 2$

Distance between given points:

$= \sqrt{(0 - \frac{ - 3}{2} ) {}^{2} + ( - 2 - 0) {}^{2} }$

$= \sqrt{( \frac{ 3}{2} ) {}^{2} + ( - 2 ) {}^{2} }$

$= \sqrt{ \frac{9}{4} + 4 }$

$= \sqrt{ \frac{9 + 16}{4} }$

$= \sqrt{ \frac{25}{4} } = \frac{5}{2}$