find the distance between two points 5/3,2/3 and -1/2,-3/2
answer it please....
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S O L U T I O N :
Given :
The two points are x & y :
- x1 = 5/3
- x2 = -1/2
- y1 = 2/3
- y2 = -3/2
Explanation :
As we know that formula of the distance :
- D = √(x2 - x1)² + (y2 - y1)²
According to the question :
➞ D = √(x2 - x1)² + (y2 - y1)²
➞ D = √(-1/2 - 5/3)² + (-3/2 - 2/3)²
➞ D = √(-1/2 - 5/3)² + (-3/2 - 2/3)²
➞ D = √(-3-10/6)² + (-9-4/6)²
➞ D = √(-13/6)² + (-13/6)²
➞ D = √(169/36) + (169/36)
➞ D = 13/6 + 13/6
➞ D = 13 + 13/6
➞ D = 26/6
Thus,
The distance between the two points will be 26/6 .
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