Question

Find the distance between two points P (-2,3) and Q (4,-5) using distance formula.

Answer 1

Answer:

10 units

Step-by-step explanation:

distance between two points is root of (x1-x2)^2 + (y1-y2)^2

so the distance between given points is

root of 6^2+ -8^2

= root of36+64

= root of 100

= 10

Answer 2

AnsWer :

10 Units.

Given :

• We have Distance PQ.
• P( -2 , 3 )
• Q( 4 , -5 )

Formula :

$\tt PQ = \sqrt{{(x_2 - x_1 ) }^{2} + {(y_2 -y_1 )}^{2} }$

Solution :

We have,

• x1 = -2.
• x2 = 4.
• y1 = 3.
• y2 = -5.

$\tt\longmapsto PQ = \sqrt{ {(4 - ( - 2))}^{2} + { (- 5 - 3)}^{2} }$

$\tt\longmapsto PQ = \sqrt{ {(6)}^{2} + {( - 8)}^{2} }$

$\tt \longmapsto PQ = \sqrt{36 + 64}$

$\tt\longmapsto PQ = \sqrt{100}$

$\tt\longmapsto PQ = 10 \: units.$

Therefore, the distance between point PQ be 10 Units.

$\rule{120}1$

Note : Graph provide above.