Question

Find the distance between two successive node or antinodes for the stationary wave if y=4sin(πx/15)cos(96πt)​

Answer 1

Answer:-

The distance between node and next anti node is 7.5 m.

Explaination:-

Answer: The distance between node and next anti node is 7.5 m.

Given that,

The wave equation is

y = 4 sin (πx/15) cos (96πt)

we know that,

The general equation is

y = a sin (2πx/Y) cos(2πt/Y)

On comparing general equation with given equations

lambda = 30λ=30

The distance between node and next anti node

d= λ/4=30=4/30

d = 7.5 md=7.5m

Hence, The distance between node and next anti node is 7.5 m.

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