find the distance bw the point (asec45 ,0)and (0,sec 45)
Answers
Answered by
1
question is wrong. acual question is (asec45,0)and(0,asec45)
Distance=root over (x1 - x2)^2 + (y1 - y2)^2
=root over (asec45 - 0)^2+(0 -a sec45)^2
=root over (a^2) (sec45)^2 + (a)^2 (sec45)^2
=root over (a)^2(root over 2)^2+ (a)^2 (root over 2)^2 [sec45=root over 2]
=root over (a)^2(2)+(a)^2(2)
=root over 4(a)^2
finally ans is '2a'
Distance=root over (x1 - x2)^2 + (y1 - y2)^2
=root over (asec45 - 0)^2+(0 -a sec45)^2
=root over (a^2) (sec45)^2 + (a)^2 (sec45)^2
=root over (a)^2(root over 2)^2+ (a)^2 (root over 2)^2 [sec45=root over 2]
=root over (a)^2(2)+(a)^2(2)
=root over 4(a)^2
finally ans is '2a'
shiva2210:
plzzz check ur question
Similar questions