Question

find the distance covered by a car in 5

second which required by a driver to stop a car which was moving with a velocity of 20 m/s​

Answer 1

Answer:

50m

Explanation:

Initial velocity = 20 m/s. Time = 5 seconds (s)

Therefore, By Newton's 3rd equation of motion,

v² - u² = 2as

(0)² - (20)² = 2as

-400 = 2as

-200 = as

S = -200/a

Now a (acceleration ) = (v-u) / t

a = (0-20)/5

a = -20/5

a = -4 m/s²

Therefore , S = -200/-4

S = 50m

Hence the distance covered is 50m

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