Question

Find the distance covered by object after applying break it attends a acceleration of 6m/s for 2minutes ?

Answer 1

v = 0......(applying break)
t = 2 * 60 sec
= 120sec

First use first equation of motion to find the value of u.

v = u + at
0 = u +(- 6 * 120)
u = 720m/sec
Here negative sign indicates retardation.

Now use third equation of motion,

v² = u² + 2as
0 = 720 + (-2*6)s
12s = 720
s = 720/12
s = 60m

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