find the distance covered by train
Answers
Answer:
1718second and it could be 1845 thousands second
Hi mate here's your answer:-
Answer:
Let the speed of the train be x km/h and the time taken by train to travel the given distance be t hours and the distance to travel was d km.
We know that,
speed= distance travelled/time taken to travel that distance
x=d/t
Or, d = xt (i)
If the train would have been 10 km/h faster, it would have taken 2 hours less than the scheduled time
⇒ (x + 10) =
⇒ (x + 10)(t - 2) = d
⇒ xt + 10t - 2x - 20 = d
From (i), we have
⇒ d + 10t - 2x - 20 = d
⇒ - 2x + 10t = 20
⇒ x - 5t = -10
⇒ x = 5t - 10 (ii)
Also,
if the train were slower by 10 km/h; it would have taken 3 hours more than the scheduled time
⇒ (x - 10) =
⇒ (x - 10)(t + 3) = d
⇒ xt - 10t + 3x - 30 = d
By using equation (i),
⇒ d - 10t + 3x - 30 = d
⇒ 3x - 10t = 30 (iii)
Substituting the value of x from eq (ii) into eq (iii), we get
⇒ 3(5t - 10) - 10t = 30
⇒ 15t - 30 - 10t = 30
⇒ 5t = 60
⇒ t = 12 hours
Putting this in eq(ii)
⇒ x = 5t - 10
= 5(12) - 10
= 50 km/h
From equation (i), we obtain
Distance to travel = d = xt
= 50 × 12
= 600 km