Question

Find the distance from a point (1, 2) to the line 5x+12y-3=0.​

Answer 1

Answer:

d = 2 units

Step-by-step explanation:

distance of point p(1, 2)  from line 5x+12y-3=0.​

let x₁ = 1 and y₁=2

so the distance d from point (x₁,y₁) to line ax+by+c = 0 is given by,

d =  $\frac {| ax_1+by_1+c|}{\sqrt{a^2+b^2} }$ units

here, d =  $\frac {| (5*1)+(12*2)-3|}{\sqrt{5^2+12^2} }$units

           =  $\frac {| (5)+(24)-3|}{\sqrt{25+144} }$units

           = $\frac {| 29-3|}{\sqrt{169} }$units

           = $\frac {| 26 |}{13 }$units

           = 2 units