Question

Find the distance from foot of tower to the top of the hill
100√3
150√3 m
120m
100m

Answer 1

Answer:

Given: Height of Tower =150 m

Angle of depression = 30

∘

∠DCB=30

∘

∠DCB=∠ABC (Alternate angles)

Let, distance of car from tower AB be x metres

In △ABC,

tan30

∘

=

AB

AC

3

1

=

x

150

x=150

3

m