find the distance from origin to the point (1,2,3)
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Step-by-step explanation:
P(1,2,3), Plane :x−y+z
F is foot of perpendicular form P to plane and I is image,then PF=FI
∴ If (x,y,z)=(r+1,−r+2,r+3) are foot of perpendicular.
⇒(r+1)−(−r+2)+r+3=5⇒r=1
∴F=(2,1,4)
∴I=(3,0,5)
∴ distance of I from origin =
√3²+√0²+√5² = 34
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