Find the distance from the center of the circle to the 30 cm length of the circle with a radius of 17 cm.
Answers
Answer:
Step-by-step explanation:
Hello Mate!
Given : Radius of circle is 17 cm and chord length = 30 cm.
Point that matter : Distance from chord to center. Thid means the distance from mid ooint of chord to the center and we know by theorum that line from centre that bisects AB is perpendicular bisector.
To find : OL.
Solution : AL = ½ AB
AL = ½ × 30 cm
AL = 15 cm
In right ∆BOL,
OB² = OL² + BL²
17² = OL² + 15²
17² - 15² = OL²
√[( 17 + 15 )( 17 - 15 )] = OL
√( 32 × 2 ) = OL
8 cm = OL
Hence radius and chord are at the distance of 8 cm.
"Have great future ahead!"
Hello Mate!
Given : Radius of circle is 17 cm and chord length = 30 cm.
Point that matter : Distance from chord to center. Thid means the distance from mid ooint of chord to the center and we know by theorum that line from centre that bisects AB is perpendicular bisector.
To find : OL.
Solution : AL = ½ AB
AL = ½ × 30 cm
AL = 15 cm
In right ∆BOL,
OB² = OL² + BL²
17² = OL² + 15²
17² - 15² = OL²
√[( 17 + 15 )( 17 - 15 )] = OL
√( 32 × 2 ) = OL
8 cm = OL
Hence radius and chord are at the distance of 8 cm.
