Find the distance from the center of the circle to the 30 cm length of the circle with a radius of 17 cm
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Answer:
Let AB be the chord with length =16cm
OA=radius=17cm
Now, OC⊥AB
Then, AC=CB=8cm (perpendicular drawn from the centre of the circle to the chord,bisects the chord)
∴OC=
(OA
2
−AC
2
=
(17
2
−8
2
)
=
(225)
=15cm
Hence, OC=15cm
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