Question

find the distance if 0.5:1:3​

Answer 1

Explanation:

We know that the distance between the two points (x1,y1) and (x2,y2) is 

d=(x2−x1)2+(y2−y1)2 

Here, the given points are (3,1) and (0,x) and the distance is 5 units, therefore,

d=(x2−x1)2+(y2−y1)2⇒5=(0−3)2+(x−1)2⇒5=(−3)2+(x−1)2⇒5=9+(x−1)2⇒52=(9+(x−1)2)

Answer 2

Answer:

Sorry friend, I don't know about that