Question

Find the distance of (-3,2).
and (3'-5
-​

Answer 1

Answer:

sqrt115

distance formula =sqrt (x1-x2)^2+(y1-y2)^2

Answer 2

Answer:

The distance between (-3,2) and (3,-5) is

$\sqrt{ {( - 3 - 3)}^{2} + {(2 + 5)}^{2} } \\ = \sqrt{36 + 49} \\ = \sqrt{85} \: \: unit$

→ $\huge\colorbox{green}{❁36+49 = 85 ❁}$

→ $\huge\colorbox{red}{❁36+49=115 is wrong ❁}$