find the distance of 4x+7y+7=0 from (1,2)along the line 2x-y=0
navu1707:
guyz its actually (1,2)
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4x+7y+7=0
4x+7y=--7 -----------------(1)eq.....
2x-y =0-----------------(2)eq......
from eq(1) and eq (2)
the answer is incomplete
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