Question

find the distance of (5,-4) from the x axis​

Answer 1

Answer:

Step-by-step explanation:

It means the distance between y-axis and the point (4,-5) is 4 and the distance between x-axis and the point (4,-5) is 5. Therefore distance of the point (4,-5) from the y-axis is 4 units.

Answer 2

Answer:-

• Given:-

The point (5,-4) are at an unknown distance from X-axis.

• To Find:-

The distance of (5,-4) from the X - axis

Formula Used::

Distance between two points (x₁ , y₁) and (x₂ , y₂) is given by:-

$\bf\boxed{\sqrt{( x_{2} - x_{1} ) ^{2} + (y _{2} - y_{1})^{2} }}$

• Solution:-

Let us consider the point on X-axis be A(5,0)

and let B(5, -4)

Now by using distance formula

$AB = \sqrt{(5 - 5) {}^{2} + ( -4 -0) ^{2} }$

$\implies \sqrt{(0)^{2} + (4)^{2}}$

$\implies \sqrt{0 + 16}$

$\implies\sqrt{16}$

$\implies\bf{4 \: units}$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬