Math, asked by biniroychacko4235, 1 year ago

Find the distance of a point (2,3,4) from the plane 3x-6y+2k=-11

Answers

Answered by ashwanisingh2001
0

 | 3 \times 2 - 6 \times 3 + 2 \times 4 + 11 \div \sqrt{ {3  }^{2} }  +  \sqrt{ {( - 6)^{2}  +  \sqrt{2^2} |

=|7|/|7|=1

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