Question

find the distance of a point (7,24) from the origin

Answer 1

diatance is
$\sqrt{7 \times 7 + 24 \times 24}$
=
$\sqrt{49 + 576}$
$= \sqrt{625}$
$= 25$
hope it will help u mark as brainlist

Answer 2

The distance of a point (7,24) from the origin is 25 unit

Given :

The points (7,24) & origin

To find :

The distance between the points

Formula :

For the given two points ( x₁ , y₁) & (x₂ , y₂) the distance between the points

$= \sf{ \sqrt{ {(x_2 -x_1 )}^{2} + {(y_2 -y_1 )}^{2} } }$

Solution :

Step 1 of 2 :

Write down the given points

The given points are (7,24) & origin (0,0)

Step 2 of 2 :

Find the distance between the points

The distance between the points (7,24) & origin (0,0)

$\sf = \sqrt{ {(7 - 0)}^{2} + {(24 - 0)}^{2} } \: \: unit$

$\sf = \sqrt{ {7}^{2} + {24 }^{2} } \: \: unit$

$\sf = \sqrt{ 49 + 576 } \: \: unit$

$\sf = \sqrt{ 625 } \: \: unit$

$\sf = 25 \: \: unit$

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