Question

find the distance of a point -8,15 from the origin

Answer 1

We know that, Distance between P(a,b) and Q(c,d) = √ ( c - a)² + ( d - b) ² Origin = ( 0 , 0 )Point P = ( x, y) Now, Distance ...

Answer 2

The distance of a point -8,15 from the origin is 17 units

Step-by-step explanation:

Points of origin =$(x_1,y_1)=(0,0)$

Another point=$(x_2,y_2)=(-8,15)$

Distance formula = $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values in the formula :

$d= \sqrt{(-8-0)^2+(15-0)^2}$

d= 17

Hence the distance of a point -8,15 from the origin is 17 units

#Learn more:

Find the distance of point (-2,3) from  origin

https://brainly.in/question/14532762#