find the distance of a point p(3,4,5) from the yz- plane
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Answered by
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Given point is P{3,4, 5).
Distance of P from yz-plane = |x coordinate of P| = 3
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The distance of a point p(3,4,5) from the yz- plane is 3 units.
Step-by-step explanation:
If a point is defined as P(x,y,z), then
Distance of point P from xy-plane = |z|
Distance of point P from yz-plane = |x|
Distance of point P from xy-plane = |z|
The given point is p(3,4,5).
So, the distance of point p from yz-plane = |3| = 3 units.
Therefore, the distance of a point p(3,4,5) from the yz- plane is 3 units.
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