Find the distance of a point p(x,y)from the origin
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From origin the distance could be calculated as the following
distance= √(x-0)²+(y-0)²
distance= √x²+ √y²
distance= √(x-0)²+(y-0)²
distance= √x²+ √y²
Answered by
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Origin = O(0,0) and P(x, y)
Let OPQ be a traingle such that Q meets at X axis with coordinates Q(x, 0)
Using Pythagoras theorem,
OP^2 = PQ^2 + OQ^2 = y^2 + x^2 which is the ans.
Please mark brainliest
Let OPQ be a traingle such that Q meets at X axis with coordinates Q(x, 0)
Using Pythagoras theorem,
OP^2 = PQ^2 + OQ^2 = y^2 + x^2 which is the ans.
Please mark brainliest
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